Can someone show me how this problem owuld look in C++ programming?

2. Write a program that reads three edges for a triangle and determines whether the input is valid. The input is valid if the sum of any two edges is greater than the third edge.





Sample Output:





Enter the first edge: 2


Enter the second edge: 2


Enter the third edge: 1


Can edges 2, 2, and 1 form a triangle? True

Can someone show me how this problem owuld look in C++ programming?
#include%26lt;iostream.h%26gt;


#include%26lt;conio.h%26gt;


main()


{


int a,b,c;


cout%26lt;%26lt; "Enter the first edge:";


cin%26gt;%26gt;a;


cout%26lt;%26lt; "Enter the second edge:";


cin%26gt;%26gt;b;


cout%26lt;%26lt; "Enter the third edge:";


cin%26gt;%26gt;c;


cout%26lt;%26lt;"Can edges"%26lt;%26lt;a%26lt;%26lt;","%26lt;%26lt;b%26lt;%26lt;", and"%26lt;%26lt;c%26lt;%26lt;"form a triangle?";


if((a+b==c)||(b+c==a)||(c+a==b))


cout%26lt;%26lt;"True";


else cout%26lt;%26lt;"False";


getch();


}
Reply:Yes. I think it can form a triangle. You can have one edge of length 2 on the left, other one on the right and the edge of 1 in the base. that can be a possibility
Reply:if you are talking about right angle triangle then let me know
Reply:I'm sure your instructor would like it better if you did it yourself. With that said, here's a little help:





1) Prompt for and read in the three values


2) Print "Can edges..." line without returning cursor


3) If all of these conditions are true, print true:


if (edge1+edge2 %26gt; edge3 %26amp;%26amp;


edge2+edge3 %26gt; edge1 %26amp;%26amp;


edge1+edge3 %26gt; edge2)


cout %26lt;%26lt; "true" %26lt;%26lt; endl;


else


cout %26lt;%26lt; "false" %26lt;%26lt; endl;

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