How to make a multiplication table using looping statement of c programming?

void main()


{


int number,i,result;





printf("Enter the number whose table is required\n");


scanf("%d",%26amp;number);





for(i=1;i%26lt;=10;i++)


{


result=number*i;


printf("\n%2dX%2d=%2d",number,i,result);


}





getch();


}

How to make a multiplication table using looping statement of c programming?
If you just want a list of numbers you just need a loop similar this





int factor;


int max_itterations;


int itterations;


factor=5;


max_itterations=12;


for (itterations = 1; itterations %26lt;= max_itterations; itterations++)


{


printf("%d ",(itterations * factor));


}





You can produce a table by introducing another loop that will display the numbers however you want them formatted.
Reply:here is the code for u





#include %26lt;stdio.h%26gt;





int main()


{


int table_size = 12;


int row = 0;


int col = 0;





for(col=0 ; col%26lt;=table_size ; col++){


printf(" %4d", col);


}


printf("\n");


for(col=0 ; col%26lt;=table_size ; col++){


printf("_____");


}





for(row = 0 ; row%26lt;=table_size ; row++){


printf("\n");


for(col = 0 ; col%26lt;=table_size ; col++) {


if(row == 0) {


if(col == 0){


printf(" ");


}else{


printf("|%4d", col);


}


}else{


if(col == 0){


printf("%4d", row);


}else{


printf("|%4d", row*col);


}


}


}


}


printf("\n");


}








try this also man





#include%26lt;stdio.h%26gt;


int main(void)


{


int i=0;


int j=0;


int result;


int d=0;


int w=1;


printf("which number you choose");


scanf("%d",%26amp;d);





result=d*j;


for(j=1;j%26lt;=10;j++)


printf("%d*%d=%d\n", d,j,d*j);


printf("\n");


return 0;


}








but this is final next time try it by yours ok
Reply:#include%26lt;stdio.h%26gt;


main()


{


int x,y;


for (x=1;x%26lt;=10;x++)


{


for (y=1;y%26lt;=10;y++)


{


printf("%dX%d=%d\n",x,y,x*y);


}


}


}